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Question

Find the oxidation number of elements in each case :

P in H3PO4,H3PO3,HPO3,P2O5 and PH3.

A
+5,+3,+5,+5,3
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B
+4,+2,+3,+5,2
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C
+5,+3,+4,+5,3
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D
None of the above
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Solution

The correct option is B +5,+3,+5,+5,3
The oxidation numbers of P in H3PO4,H3PO3,HPO3,P2O5 are +5,+3,+5,+5,3 respectively.
Let X be the oxidation number of P in H3PO4.
3+X+4(2)=0
X=+5
Let X be the oxidation number of P in H3PO3
3+X+3(2)
X=+3
Let X be the oxidation number of P in HPO3
1+X+3(2)
X=+5
Let X be the oxidation number of P in P2O5
2X+5(2)=0
X=+5
Let X be the oxidation number of P in PH3
X+3=0
X=3

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