Find the oxidation number of $M n$ in $[M n O_{4}]^{-}$ ion.

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Solution

Let oxidation number of $M n$ be $x$ .
We know that, Ox. no. of $O = - 2$ .
So, Ox. no. $M n$ + 4(Ox. no. $O$ ) $= - 1$
$x + 4 (- 2) = - 1$
or $x - 8 = - 1$
or $x = + 8 - 1 = + 7$
The oxidation number of $M n$ in $[M n O_{4}]^{-}$ ion is $+ 7$ .

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