Question

Oxidation number of $Mn$ in $Mn{O}_2,Mn{O}_4^{2-},Mn{O}_4^{-}$ are $4$, $+6$ and $+7$ respectively.
If true enter 1, else enter 0.

• A. 1

Answer 1

The correct option is A 1
Let $x$ be the oxidation number of Mn in $Mn{O}_2$.
Since the overall
charge on the complex is $0$, the sum of oxidation states of all elements in
it should be equal to $0$.
Therefore, $x+2(-2)=0$
$x=+4$
Similarly,
Let $y$ be the oxidation number of Mn in $Mn{O}_4^{2-}$
$y+4(-2)=-2$
$y=+6$
Let $z$ be the oxidation number of Mn in $Mn{O}_4^{-}$
$z+4(-2)=-1$
$z=+7$
Thus, the oxidation number of $Mn$ in $Mn{O}_2,Mn{O}_4^{2-},Mn{O}_4^{-}$ are $4$, $+6$ and $+7$ respectively.