Find the oxidation number of Ni in $N i (C O)_{4}$ .

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Solution

Let X be the oxidation number of Ni in $N i (C O)_{4}$ .
The O atoms have oxidation number of -2.
The C atoms have oxidation number of+2.
$X + 4 (+ 2 - 2) = 0$
$X + 4 (0) = 0$
$X + 0 = 0$
$X = 0$
The oxidation number of Ni in $N i (C O)_{4}$ is $0$ .

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