Question

Find the oxidation number of Xe in $BaXe{O}_6$.

Answer 1

Oxidation state of $Ba$ in general $=+2$ and of $O=-2$

Applying formula, $\text{Sum of total oxidation state of all atoms}=\text{Overall charge on the compound}.$

Let oxidation state of $Xe$ in $BaXe{O}_6$ be $x$.

$2+x+6(-2)=0,x=10$

But oxidation state $10$ is not possible for $Xe$ . In this case the oxidation state of $Xe$ is equal to maximum possible oxidation state for $Xe=+8$