Find the perimeter of a $∆ A B C$ whose:
$A B = 6 c m, B C = 7 c m, C A = 8 c m$

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Solution

Given $A B = 6 c m, B C = 7 c m, C A = 8 c m$
The perimeter of a shape is defined as the total distance around the shape. It is the length of the outline or boundary of any two-dimensional geometric shape.
Perimeter of $∆ A B C$ $= A B + B C + C A$
$= 6 + 7 + 8 = 21 c m$
Hence perimeter of a $∆ A B C$ is $21 c m$

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