Find the perimeter of a rectangle whose length is $40$ cm and diagonal is $41$ .

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Solution

$l = 40 c m$ , $d = 41$ , $b = \sqrt{(41)^{2} - (40)^{2}} = 9$
$∴$ Perimeter= $2 (l + b) = 2 (49) = 98 c m$

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