Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm

Open in App

Solution

$B C = \sqrt{41^{2} - 40^{2}}$
$= \sqrt{(41 + 40) (41 - 40)}$
$= \sqrt{81}$
BC=9
Perimeter = 2(AC+BC) = 2(40+9) = 2(49) = 98 cm

Suggest Corrections

Similar questions

Find the perimeter of a rectangle whose length is $40 c m$ and a diagonal is $41 c m$ .

Find the perimeter of rectangle whose length is $40$ cm and diagonal is $41$ cm.

Question 7
Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41cm.

40

41

The diagonal of a rectangle $\sqrt{41} c m$ and its area is 20 sq. cm. The perimeter of the rectangle must be:

Join BYJU'S Learning Program