Find the perimeter of a rectangle whose length is thrice of its breadth. Consider the breadth of the rectangle as ‘b’ m.

'4b' m

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'6b' m

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'8b' m

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'10b' m

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Solution

The correct option is C '8b' m
Breadth = ‘b’ m
Length = 3 $\times$ b = ‘3b’ m
Perimeter of rectangle = 2(length + breadth) = 2(3b + b) = 2(4b) = ‘8b’ m

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