Find the perimeter of the rectangle whose length of one side is 12 cm and the length of the diagonal is 13 cm.
34 cm
For calculating the perimeter of rectangle, we require both length and breadth.
Perimeter = 2(length + breadth)
From the figure given,
AB = CD = 12 cm
△BCD is right angled at C.
So, by using Pythagoras' theorem,
BC2 + DC2 = BD2
Hence, BC2 = BD2 - DC2
Now, BD = 13 cm, DC = 12 cm
So, BC2 = 132 - 122
⇒ BC2 = 25 cm2
⇒ BC = 5 cm
Hence, the breadth of the rectangle is 5 cm.
So, perimeter = 2(length + breadth)
= 2(BC + DC)
= 2(5 + 12)
= 2×17
= 34 cm