Find the perimeter of the rectangle with the lengths and breadths as follows:
( $0.1$ m and $9$ cm

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Solution

Given: Length $= 0.1 m$ and Breadth $= 9 cm$
As, $1$ m $= 100$ cm
$\Rightarrow 0.1$ m $= 0.1 \times 100$
$= 10$ cm
Perimeter of rectangle $= 2 \times$ (length $+$ breadth)
So, Perimeter $= 2 \times (10 + 9)$ cm
$= 2 \times 19 = 38 cm$
Hence, the required perimeter is $38$ cm.

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