Find the Perimeter of the Square ADEC given in the figure.

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4 $\sqrt{2}$

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2 $\sqrt{2}$

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2 $\sqrt{3}$

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Solution

The correct option is B
4 $\sqrt{2}$

ABC is a right angled triangle.

AC = $\sqrt{1^{2} + 1^{2}}$ = $\sqrt{2}$

Perimeter of the Square ADEC = 4 $\times$ $\sqrt{2}$ = 4 $\sqrt{2}$

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