Find the point of intersection of
$2 x - 3 y + 5 = 0$ and $x + 4 y - 14 = 0$ .

Open in App

Solution

$2 x - 3 y + 5 = 0 x + 4 y - 14 = 0 x = 14 - 4 y 2 (14 - 4 y) - 3 y + 5 = 0 28 - 8 y - 3 y + 5 = 0 33 - 11 y = 0 y = 3 x = 14 - 12 = 2$

Suggest Corrections

Similar questions

k x + 4 y + 2 = 0, x - 3 y + 5 = 0

2 x + 7 y - 3 = 0

u = 2 x + 4 y a n d v = x - 3 y + 5

77 u - 89 v = 0

87 u + 98 v = 0

Find the coordinates of the intersection of the lines $2 x - 3 y + 1 = 0$ and $2 x + 4 y + 5 = 0$ .

x - y - 1 = 0

2 x - 3 y + 1 = 0

3 x + 4 y - 14 = 0

2 x - 3 y + 5 = 0

3 x + 4 y = 0

5 x - 2 y = 0

Join BYJU'S Learning Program