Find the point of intersection of the line $3 x - y + 1 = 0$ and $x + y = 5$

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Solution

$x + y = 5$

$y = 5 - x$

$3 x - y + 1 = 0$

$y = 1 + 3 x$

$5 - x = 1 + 3 x$

$4 x = 4$

$x = 1$

$⟹ y = 4$

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Find the point of intersection of the line 3x−y+1=0 and x+y=5

x+y=5y=5−x3x−y+1=0y=1+3x5−x=1+3x4x=4x=1⟹y=4

Find the point of intersection of the line $3 x - y + 1 = 0$ and $x + y = 5$

$x + y = 5$

$y = 5 - x$

$3 x - y + 1 = 0$

$y = 1 + 3 x$

$5 - x = 1 + 3 x$

$4 x = 4$

$x = 1$

$⟹ y = 4$