Question

Find the point where the graph of the equations $3x+4y=12$ cuts the $x-$axis and the $y-$axis.

Answer 1

3x + 4y = 12

the point on y axis

let x = 0 ,so 3(0) + 4y = 12 , 4y = 12, y = 3

point is ( 0, 3)

the point on x axis

let y =0,so 3x + 4(0) =12, 3x = 12, x= 4

point is (4,0)