Find the position of centre of mass from base of a solid hemisphere of radius $16 c m .$

4 c m

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6 c m

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8 c m

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12 c m

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Solution

The correct option is D $6 c m$
The centre of mass from the base of hemisphere is given as

$C . O . M = \frac{3}{8} R$

By substituting the value of radius in the above equation we get

$C . O . M = \frac{3}{8} \times 16 = 6 c m$

Hence, the position of C.O.M. is $6 c m$

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Question 15
If three cubes each of edge 4 cm are placed end to end, then the dimensions of resulting solid are

a) $12 c m \times 4 c m \times 4 c m$

b) $4 c m \times 8 c m \times 4 c m$

c) $4 c m \times 8 c m \times 12 c m$

d) $4 c m \times 6 c m \times 8 c m$

12 c m

6 c m

c m

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