Question

Find the potential difference between A and B $(V_A-V_B)$ for the given circuit

• A. $6\text{V}$
• B. $14\text{V}$
• C. $10\text{V}$
• D. $12\text{V}$

Answer 1

The correct option is B $14\text{V}$

From the direction of current given in the circuit, the potential of point $A$ will be greater than the potential of point $B$, because current flows from region of high potential to low potential.

Traversing in the direction of current from $A$ to $B$ we get,
$V_A-iR-E-V_B=0$
$\Rightarrow V_A-V_B=iR+E$
$\therefore V_A-V_B=4+10=14\text{V}$