Find the potential difference between the final and initial points.
A
−4×103V
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B
−4×104V
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C
4×103V
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D
4×104V
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Solution
The correct option is B−4×104V Since the field is uniform, the potential difference will be given by the product of the electric field and the distance. so it will be 8×0.5×104=4×104V
Proton being positively charged will always move from higher potential to a lower potential. Since it is stated as PD between final and initial, it is lower-higher, hence it is negative.