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Liquid Pressure

Find the pres...

Question

Find the pressure at a depth of $0.6 m$ in water of density $1000 k g$ $m^{- 3}$ .(Take $g = 10 m$ $s^{- 1}$ )

6000

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600

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6

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0.6

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Solution

The correct option is A $6000$
$6000 P a$

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Similar questions

g = 10 m / s^{2}

1000 k g / m^{3})

6 m

= 1000 k g

m^{- 3}

g = 10 m s^{- 2}

10 m

= 1000 k g

m^{- 3}

g = 10 m

s^{- 2}

p \times 10^{5} P a

\frac{2}{3} r d

10^{5} Pa

1000 {kg/m}^{3}

g = 10 {m/s}^{2}

120000 P a

30000 P a

g = 10 m

s^{- 2}

= 1000 k g

m^{- 3}

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