Find the pressure of krypton in the manometer .(in torr)

475

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375

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400

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300

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Solution

The correct option is B 375
Given : $P_{B} = 725$ mm Hg
Difference in height in mercury column $h = 54 - 19 = 35$ cm $= 350$ mm
From figure, $P_{A} = P_{B}$ where $P_{A} = P_{k r} + P_{c o l u m n}$
$∴$ $P_{K r} + 350$ mm Hg $= 725$ mm Hg
$⟹$ $P_{c o l u m n} = 725 - 350 = 375$ mm Hg or $375$ torr

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Find the pressure of krypton in the manometer .(in torr)

The correct option is B 375Given : PB=725 mm Hg Difference in height in mercury column h=54−19=35 cm =350 mm From figure, PA=PB where PA=Pkr+Pcolumn∴ PKr+350 mm Hg =725 mm Hg⟹ Pcolumn=725−350=375 mm Hg or 375 torr