Find the probability of 53 Friday in a leap year
1 year = 365 days
A leap year has 366 days
A year has 52 weeks.
Hence there will be 52 Sundays for sure.
52 weeks = 364 days
366 – 364 =2 days
In a leap year, there will be 52 Sundays and 2 days will be left.
These 2 days can be:
Sunday, Monday
Monday, Tuesday
Tuesday, Wednesday
Wednesday, Thursday
Thursday, Friday
Friday, Saturday
Saturday, Sunday
Of these total 7 outcomes, the favorable outcomes are 2.
we know P(A)= S/A. {where S= 2 days & A= 7 days}
so,
P(A)=2/7 = 0.28
Hence the probability of getting 53 days is 2/7 or 0.28 (ans).