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Question

Find the probability of 53 Friday in a leap year

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Solution

1 year = 365 days

A leap year has 366 days

A year has 52 weeks.

Hence there will be 52 Sundays for sure.

52 weeks = 364 days

366 – 364 =2 days

In a leap year, there will be 52 Sundays and 2 days will be left.

These 2 days can be:

Sunday, Monday

Monday, Tuesday

Tuesday, Wednesday

Wednesday, Thursday

Thursday, Friday

Friday, Saturday

Saturday, Sunday

Of these total 7 outcomes, the favorable outcomes are 2.

we know P(A)= S/A. {where S= 2 days & A= 7 days}
so,
P(A)=2/7 = 0.28

Hence the probability of getting 53 days is 2/7 or 0.28 (ans).


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