Question

Find the probability of getting $52$ Sundays in a non-leap year.

Answer 1

Step 1: Find the number of days

A non-leap year has $365$ days.

A year has $52$ weeks

Hence there will be $52$ Sundays for sure

$52$ week$=52\left(7\right)=364$ which means one day is extra

This one day might be Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Step 2: Probability of getting $52$ Sundays in a non-leap year

Of these seven totals mentioned above, the favorable outcome is one,

Therefore, probability of getting $53$ Sundays is $\frac{1}{7}$

Probability of getting $52$ Sundays in $52$ weeks ($364$ days) is one.

The probability of getting $52$ Sundays in a non-leap year ($365$ days)

$1-\frac{1}{7}=\frac{6}{7}$

Thus, the probability of getting $52$ Sundays in a non-leap year $=\frac{6}{7}$.