Question

Find the probability of getting a multiple of 2 on one die and a multiple of 3 on the other die, if pair of dice are thrown.

• A.
  $\frac{5}{18}$
• B.
  $\frac{1}{3}$
• C.
  $\frac{11}{36}$
• D.
  $\frac{1}{4}$

Answer 1

The correct option is A

$\frac{5}{18}$

Total no. of outcomes = 36
Favourable outcomes = {(2, 3), (2, 6),(3, 2), (3, 4), (3, 6), (4, 3),(4, 6), (6, 2), (6, 4), (6, 6).
No. of favourable outcomes = 10
For an event $\text{E, Probability P(E)}$
$=\frac{\text{Number of outcomes favourable to E}}{\text{Number of all possible outcomes of the experiment}}$

$\therefore$ $\text{Required probability}$ $=\frac{10}{36}=\frac{5}{18}$