Find the probability of getting a multiple of 3 on one die and multiple of 2 on the other die when two dice are thrown simultaneously?
11/36
Let X be required events and S be the sample space.
then X = {(2,3),(2,6),(4,3),(4,6),(6,3),(6,6),(3,2),(6,2),(3,4),(6,4),(3,6)}
n(X) = 11, n(S) =36
Hence, required probability =n(X)n(S) = 1136