Question

Find the probability of getting a number more than $4$ by throw of an ordinary dice.

Answer 1

Total number of events $=6$
No. of favourable events $(5,6)=2$
Hence, the required probability is
$=\frac{\text{No. of favourable events}}{\text{Total no. of events}}=\frac{2}{6}=\frac{1}{3}$