Question

Find the probability of getting at least two heads if three coins are tossed simultaneously.

• A. $\frac{1}{8}$
• B. $\frac{3}{8}$
• C. $\frac{1}{2}$
• D. $\frac{3}{4}$

Answer 1

The correct option is C

$\frac{1}{2}$

The possible outcomes when three coins are tossed simultaneously is {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}, where H represents the head and T represents the tail.
There are four favourable outcomes for getting at least two heads: HHT, HTH, THH and HHH, out of a total of 8 possible outcomes.
We know that, Probability of an event E, P(E) =$\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$
Hence, the required probability = $\frac{4}{8}$ = $\frac{1}{2}$