Question

Find the probability that a leap year selected at random contains 53 Tuesdays.

Answer 1

In Leap Year,

There are $366$ days,

$366$ days = $52$ weeks $+2$days

These $2$ days can be

$MT,TW,WTh,ThF,FSa,SaS,SM$
$n\left(S\right)=7$

Event , E: Getting Tuesday
$n\left(E\right)=2$

Hence $P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{2}{7}$

Hence the probability of $53$ Tuesdays $=\frac{2}{7}$