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Question

Find the product using appropriate identity:
(abc)(a2+b2+c2+abbc+ca)

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Solution

We know the identity (a+b+c)(a2+b2+c2abbcca)=a3+b3+c33abc

Using the above identity taking a=a, b=b and c=c, the product (abc)(a2+b2+c2+abbc+ca) can be computed as follows:

(abc)(a2+b2+c2+abbc+ca)=a3+(b)3+(c)3(3a×b×c)=a3b3c33abc

Hence, (abc)(a2+b2+c2+abbc+ca)=a3b3c33abc


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