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Question

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(ab2) × (−b2c) × (−a2c3) × (−3abc)

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Solution

=(-3×-1×-1)×(a×a2×a×b2×b2×b×c×c3×c=-3×a(1+2+1)×b(2+2+1)×c(1+4+1)=-3a4b5c5

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