Find the quadratic equation in $x$ , whose solutions are $3$ and $2$ .

x^{3} - 5 x + 6 = 0

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x^{2} - 5 x + 6 = 0

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x^{2} - 3 x + 6 = 0

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x^{2} - 5 x + 7 = 0

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Solution

The correct option is C $x^{2} - 5 x + 6 = 0$
The solution of $x$ in the form of $(x - 3) (x - 2) = 0$
By multiplying, we get
$x^{2} - 2 x - 3 x + 6 = 0$
Therefore, the quadratic equation is $x^{2} - 5 x + 6 = 0$

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