Question

Find the quotient: $(-9a^{10})÷(-3a^9)$

Answer 1

Divide ${-9a}^{10}$ by $-3a^9$ as follows:

$\frac{-9a^{10}}{-3a^9}=\frac{-9}{-3}(a^{10}\times a^{-9})=3\left(a^{10-9}\right)=3a(\because \frac{1}{a^2}=a^{-2},a^x\times a^y=a^{x+y})$

Hence, $\frac{-9a^{10}}{-3a^9}=3a$