Find the Quotient and the Remainder when the first polynomial is divided by the second.
$(6 x^{2} - 31 x + 47)$ by $(2 x - 5)$

Q u o t i e n t = 3 x - 8, R e m a i n d e r = 7

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Q u o t i e n t = 3 x + 8, R e m a i n d e r = 7

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Q u o t i e n t = - 3 x - 8, R e m a i n d e r = 7

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Q u o t i e n t = - 3 x + 8, R e m a i n d e r = 7

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Solution

The correct option is B $Q u o t i e n t = 3 x - 8, R e m a i n d e r = 7$
quotient = $3 x - 8$ , remainder = $7$

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Similar questions

When the polynomial f(x) = 4x³ + 8x² + 8x + 7 is divided by the polynomial g(x) = 2x² - x + 1, the quotient and the remainder are

(2 x^{3} - 5 x^{2} + 8 x - 5)

(2 x^{2} - 3 x + 5)

Write the quotient and remainder when we divide.

$(6 x^{2} - 31 x + 47) b y (2 x - 5)$

6 x^{2} + x - 15

3 x + 5

3 x^{4} + 6 x^{3} - 6 x^{2} + 2 x - 7

x - 3

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