Find the quotient when polynomial $2 x^{3} + 6 x^{2} + 7 x + 60$ is divide by $2 x^{2} - 2 x + 15$

x + 3

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x + 2

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x + 1

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x + 4

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Solution

The correct option is D
x + 4

$\begin{matrix} x + 4 2 x^{2} - 2 x + 15 & 2 x^{3} + 6 x^{2} + 7 x + 60 2 x^{3} - 2 x^{2} + 15 x - + - 8 x^{2} - 8 x + 60 8 x^{2} - 8 x + 60 - + - 0 \end{matrix}$

Quotient = x + 4

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Similar questions

Q. The quotient

q (x)

is when the polynomial

(x^{4} + x^{3} - 2 x^{2} + x - 1)

is divided by

(x - 1)

Quotient and remainder of a polynomial when divided by x+2 are 2x-1 and 3 respectively. Find the polynomial.

Find the Quotient and the Remainder when the first polynomial is divided by the second.

(x^{4} - 2 x^{3} + 2 x^{2} + x + 4)

(x^{2} + x + 1)

Priya lost her homework paper on polynomials and she doesn't remember the divisor dividing the polynomial $x^{3} - 3 x^{2} + x + 2$ gives quotient $x - 2$ and remainder $- 2 x + 4$ . Find the divisor.

Priya lost her homework paper on polynomials and she doesn't remember the divisor dividing the polynomial $x^{3} - 3 x^{2} + x + 2$ which gives quotient $x - 2$ and the remainder $- 2 x + 4$ . Find the divisor.

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Find the quotient when polynomial 2x3+6x2+7x+60 is divide by 2x2−2x+15

The correct option is D x + 4 x+42x2−2x+152x3+6x2+7x+602x3−2x2+15x− + − 8x2−8x+608x2−8x+60− + − 0 Quotient = x + 4

Find the quotient when polynomial $2 x^{3} + 6 x^{2} + 7 x + 60$ is divide by $2 x^{2} - 2 x + 15$

The correct option is D
x + 4

$\begin{matrix} x + 4 2 x^{2} - 2 x + 15 & 2 x^{3} + 6 x^{2} + 7 x + 60 2 x^{3} - 2 x^{2} + 15 x - + - 8 x^{2} - 8 x + 60 8 x^{2} - 8 x + 60 - + - 0 \end{matrix}$

Quotient = x + 4