Find the radius of circle which has arc length of $37.4 c m$ making angle $60^{o}$ with centre. (Take $π = \frac{22}{7}$ )

Open in App

Solution

Given arc is making an angle $60^{\circ}$ at the center.
length of the arc $= 37.4 c m$
$⟹ \frac{π}{180^{\circ}} \times 60^{\circ} \times r = 37.4$
$⟹ \frac{π}{3} \times r = 37.4$
$⟹ r = 37.4 \times \frac{3}{π} = 37.4 \times 3 \times \frac{7}{22} = 112.2 c m$

Suggest Corrections

Similar questions

The arc of a circle of radius $21 c m$ subtends an angles of $60^{o}$ at the center, find the length of the arc.(in cm) (Take $π = 22 / 7$ ).

r a d i u s o f c i r c l e = 5.5 m, l e n g t h o f a r c = 6.05 m [π = \frac{22}{7}]

60^{o}

[U s e π = \frac{22}{7}]

Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cm $(use π = \frac{22}{7})$ .

Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cm.

Join BYJU'S Learning Program