Find the radius of gyration of a thin uniform rod of mass M and length L=3 m about an axis passing through one end and perpendicular to rod as shown in figure.
A
3m
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B
√3m
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C
1√3m
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D
1m
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Solution
The correct option is B√3m
As we know, Moment of inertia of a rod of mass M about Iz=ML23.
The radius of gyration of rod about about Iz is given by K=√IM K=
⎷ML23M=√13×L =1√3×3m