Question

Find the ratio in which point $T(-1,6)$ divides the line segment joining the points $S(-3,10)$ and $R(6,-8)$.

Answer 1

Let $\frac{SI}{TR}=\frac{R}{1}$

From section's formula,

$-1=\frac{6R-3}{RH}$

$\Rightarrow 6R-3=-R-1$

$\Rightarrow 7R=2$

$\Rightarrow R=\frac{2}{7}$

$\Rightarrow \frac{ST}{TR}=\frac{2}{7}$

$\Rightarrow$ T divides SR is $2:7$ ratio.