Find the reading of the spring balance if M is in equilibrium. Assume all surfaces to be smooth. Take g=10m/s2.
A
1kg
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B
1.2kg
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C
1.4kg
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D
1.6kg
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Solution
The correct option is B1.2kg The FBDs of the blocks are as shown.
As we know, the spring balance reads the value of spring force kx
So, from the FBDs, we have N=2.5gcos37∘
and, kx=Ncos53∘=(2.5gcos37∘).cos53∘ ⇒kx=2.5×10×45×35 ⇒kx=12N
Thus, the equivalent mass shown by the spring balance is 12g=1210=1.2kg