Find the remainder using remainder theorem, when:
$2 x^{3} - 4 x^{2} + 7 x + 6$ is divided by $x - 2$

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Solution

According to remainder theorem when $f (x)$ is divided by $(x - 2)$ , Remainder $= f (2)$
$f (x) = 2 x^{3} - 4 x^{2} + 7 x + 6$
$f (2) = 2 (2)^{3} - 4 (2)^{2} + 7 (2) + 6$
$= 16 - 8 + 14 + 6 = 28$
$∴$ Remainder $= 28$

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