Question

Find the remaining members of a Pythagorean triplet whose smallest member is 8.

• A. 15, 16
• B. 14, 15
• C. 14, 16
• D. 15, 17

Answer 1

The correct option is D 15, 17

We can get Pythagorean triplet by using the general form:
$2m$, $m^2-1$, and $m^2+1$.
Let, $2m=8$
So, $m=4$
$\therefore m^2-1=4^2-1=16-1=15$
And, $m^2+1=4^2+1=16+1=17$
Thus, the Pythagorean triplet is 8, 15, 17.

So, the remaining members of the Pythagorean triplet are 15, 17.