Question

Find the remiander if we divide $(15y^4-16y^3+9y^2-\frac{1}{3}y-\frac{50}{9})$ by $(3y-2)$

Answer 1

$(15y^4-16y^3+9y^2-\frac{1}{3}y-\frac{50}{9})=(3y-2)y+R$

Put $y=2/3$ in the above equation we get

$D+R=\frac{-32}{9}\Rightarrow R=-\frac{-32}{9}$