Question

Find the root of the quadratic equation $x^2-3x-10=0$.

Answer 1

given, $x^2-3x-10=0$

$x^2-5x+2x-10=0$

$x(x-5)+2(x-5)=0$

$(x-5)(x+2)=0$

$x=-2,5$ are the roots of the given equation.