Question

Find the roots of
$3x^2+13x-10=0$

Answer 1

We have,

$3x^2-13x-10=0$

$(3x+2)(x-5)=0$

$3x+2=0$, $x-5=0$

$-2=-2$, $x=5$

$\frac{3x}{3}=\frac{-2}{3}$

$\therefore x=\frac{-2}{3}$

Hence, this is answer.