Question

Find the roots of the equation $2x^2-3x+6$ using quadratic formula.

Answer 1

$2x^2-3x+6=0$ is of the form $a{x}^2+bx+c=0$ where $a=2,b=-3,c=6$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{3\pm \sqrt{2^2-4\times 2\times 6}}{2\times 2}$

$\Rightarrow x=\frac{3\pm \sqrt{4-48}}{4}$

$\Rightarrow x=\frac{3\pm \sqrt{-40}}{4}$

$\Rightarrow x=\frac{-3\pm \sqrt{-4\times 10}}{4}$

$\therefore x=\frac{-3\pm 2i\sqrt{10}}{4}$