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Question

Find the roots of the equation: :25a235a+12.

A
(5a3)(5a4)
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B
(5a3)(5a+4)
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C
(5a+3)(5a4)
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D
(5a+3)(5a+4)
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Solution

The correct option is C (5a3)(5a4)
25a25a+12=0
25a220a15a+12=0
5a(5a4)3(5a4)=0
(5a4)(5a3)=0
a=35,45

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