Find the roots of the equation 2 x 2-4 x -6-0A- -1 -3 i- -1 -2 i- -1 -5 iD- -1 -7 i

The correct option is B Equation 2x^2+4x+ 6 =0 x = b ±√(b^2 4ac)/2a = 4 ±√(16 4 × 2 × 6)/2 × 2 = 4 ±√(( 32))/4 = 4 ± 4√((2i))/4 = 1 ±√(2)i ...

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How to Find the Inverse of a Function

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Find the roots of the equation $2 x^{2} + 4 x + 6 = 0$

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Find the roots of the quadratic equation 3 x^{2} + 2 x - 1 = 0.

Find the sum of roots and product of roots respectively for $2 x^{2} + x - 5 = 0$

2 x^{2} - x + a = 0 (a \in R)

(1, 2),

- 1 < a \leq \frac{1}{8}

f (x) = 2 x^{2} - x + a,

D \geq 0, f (1) > 0,, f (2) > 0

- 1 < a \leq \frac{1}{8}

\sqrt{\frac{2 x^{2} + 1}{x^{2} - 1}} + 6 \sqrt{\frac{x^{2} - 1}{2 x^{2} + 1}} = 5

If $α, β$ are the roots of the equation $2 x^{2} + 5 x + 6 = 0$ , then find the equation whose roots are $\frac{1}{α} a n d \frac{1}{β}$ .

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