Find the roots of the quadratic equation 3 x2-2 x-1-0A- 1B- -1 C- 1-3D- -1-3

The correct options are B 1 C 1/3Given: 3x^2+2x 1 = 0 ⇒ 3x^2+3x x 1 = 0 ⇒ 3x (x+1) 1 (x+1) nbsp;= 0 ⇒ (3x 1) (x+1) = 0 ⇒ (3x 1)=0 or (x+1)=0 ⇒ x = 1/3 or x ...

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Byju's Answer

Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

Find the root...

Question

$Find the roots of the quadratic equation 3 x^{2} + 2 x - 1 = 0.$

1

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\frac{1}{3}

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\frac{- 1}{3}

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Solution

The correct options are
B $- 1$
C $\frac{1}{3}$
$Given: 3 x^{2} + 2 x - 1 = 0 \Rightarrow 3 x^{2} + 3 x - x - 1 = 0 \Rightarrow 3 x (x + 1) - 1 (x + 1) = 0 \Rightarrow (3 x - 1) (x + 1) = 0 \Rightarrow (3 x - 1) = 0 o r (x + 1) = 0 \Rightarrow x = \frac{1}{3} o r x = - 1 ∴ The roots of the given equation are - 1, \frac{1}{3} .$

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The roots of the quadratic equation $3 x^{2} - 2 x - 1 = 0$ are 1 and $- \frac{1}{3}$ . From this information, determine which of the following options will be the zeros of the quadratic polynomial $3 x^{2} - 2 x - 1$

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Find the roots of the quadratic equation 3x2+2x−1=0.

The correct options are B −1 C 13Given: 3x2+2x−1=0⇒3x2+3x−x−1=0⇒3x(x+1)−1(x+1)=0⇒(3x−1)(x+1)=0⇒(3x−1)=0 or (x+1)=0⇒x=13 or x=−1∴The roots of the given equation are −1,13.

$Find the roots of the quadratic equation 3 x^{2} + 2 x - 1 = 0.$