The correct option is D x = 1, -1
Roots of the quadratic equation ax2+bx+c=0 can be found out by using the quadratic formula, given by,
x=−b±√b2−4ac2a.
Given, x2−1=0
x2−1=0 can be written as x2+0x−1=0.
Then, a = 1, b = 0 and c = -1.
⇒x=−0±√02−(4×1×−1)2×1 =±√42 =±1
Therefore, the roots of x2−1=0 are x=1 and x=−1.