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Question
If (1 - p) is a root of quadratic equation x2+px+(1−p)=0 then its roots are
If (1 - p) is a root of quadratic equation x2+px+(1−p)=0 then its roots are
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Solution
The correct option is C 0, -1
Let the second root be α,
Then α+(1−p)=−p⇒α=−1
Also α.(1−p)=1−p⇒(α−1)(1−p)=0⇒p=1[∵α=−1]
∴ Roots are α=−1 and p−1=0
Let the second root be α,
Then α+(1−p)=−p⇒α=−1
Also α.(1−p)=1−p⇒(α−1)(1−p)=0⇒p=1[∵α=−1]
∴ Roots are α=−1 and p−1=0
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