Find the roots of the following quadratic equations by using the quadratic formula
$3 a^{2} x^{2} + 8 a b x + 4 b^{2} = 0, a \neq 0$

\frac{2 b}{a}, \frac{- 2 b}{3 a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 3 b}{2 a}, \frac{- 2 b}{3 a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 2 b}{a}, \frac{2 b}{3 a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 2 b}{a}, \frac{- 2 b}{3 a}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{- 2 b}{a}, \frac{- 2 b}{3 a}$
Given,
$3 a^{2} x^{2} + 8 a b x + 4 b^{2} = 0$
$=> 3 a^{2} x^{2} + 6 a b x + 2 a b x + 4 b^{2} = 0$
$=> 3 a x (a x + 2 b) + 2 b (a x + 2 b) = 0$
$=> (a x + 2 b) (3 a x + 2 b) = 0$
$=> a x + 2 b = 0$ and $3 a x + 2 b = 0$
$=> x = - \frac{2 b}{a}$ and $x = - \frac{2 b}{3 a}$

Suggest Corrections

Similar questions

3 a^{2} x^{2} + a b x - 2 b^{2} = 0

a^{4} - 3 a^{2} b^{2} + b^{4}

3 a^{4} - 2 a^{2} b^{2} + b^{4} + 3 a^{2} b + 2 a b^{2} .

\frac{3 a}{2 b} - \frac{2 b}{3 a}

8 (3 a - 2 b)^{2} - 10 (3 a - 2 b)

Join BYJU'S Learning Program