Question

Find the roots of the quadratic equation $a{x}^2+bx+c=0$.

• A. $x=\frac{-b\pm \sqrt{b^2-4ac}}{2}$
• B. $x=\frac{-b+\sqrt{b^2-4ac}}{4a}$
• C. $x=\frac{-b-\sqrt{b^2-4ac}}{4a}$
• D. $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Answer 1

The correct option is D $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

The formula for the roots of the quadratic equation $a{x}^2+bx+c=0$ is given as

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{-b+\sqrt{b^2-4ac}}{2a}and\frac{-b-\sqrt{b^2-4ac}}{2a}\text{are the roots of the equation.}$